सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

426
[चित्र: Fig. 95]
Fig. 95
be had for an arbitrary H cos ZV ? The result is
(H cos ZV / 3438) × H sin 24 since 4 nādīs correspond to 24°,
60 nādīs corresponding to 360°. Hence the result is
(H cos ZV × 1397) / 3438 . Converting 3438 / 1397 into a continued
fraction we have 2 + 1/(2+) 1/(5+) 1/(1+) 1/9 ......of which the con-
vergents are 2/1, 5/2, 27/11, 32/13 and 32/13 is a very good convergent
preceding a large quotient namely 9. So the result may
be written as (13 H cos ZV) / 32 which is symbolized as Para.
Now parallax in longitude = (Para × H siu ( ☉ − v )) / R .
When H sin ( ☉ − v ) = R, the parallax will be equal to