सामग्री पर जाएँ
सर्वकोश
सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

Siddhanta Shiromani Ganitadhyaya of Bhaskaracharya with Commentary

भास्कराचार्य द्वितीय द्वारा

DevanagariHindipublished573 पृष्ठ

पृष्ठ 328, कुल 573 में से

संदर्भ में पढ़ें
पृष्ठ 328

308
to directions (not of signs) namely that a is south if δ is
north, s is always north and b is to be taken to belong to
that direction to which the numerically bigger quantity of
a and s belongs in the case of difference. Also it is to be
taken to belong to that direction of a and s when both of
them have the same direction.
With this convention in mind, Bhāskara clarifies the
convention by citing examples.
(1) S=5, δ is north, Agrā=916'-48'' K=30 so that
a = KA / R = (916⅘ × 30) / 3438 = 8 units (south, because it should
be taken to be व्यस्तगोला ie. belonging to the direction
opposite to that of δ).
Question. "What is b and of what direction?"
Answer. b = a +~ s = 8 (south) ~ 5 (north). (We are
taking the difference because Samskāra is to be construed
as addition of quantities having the same direction and
difference of quantities of opposite direction ∴ b = 3
and is on the south because the numerically bigger quantity
of 8 and 5 belongs to south.
Q. 2. δ is north S=5, A=916'-48'' ; K=15, 'what
is b and in what direction?'
Answer. a = KA / R = 4; b = a +~ s = 4 +~ 5 = 4~5 (here
a is south δ being north and s is north so that difference
is stipulated as above) = 1 (north because 5 belongs to
north.
We add here two more examples to illustrate addition
by saying that δ is south in the above examples so that a
is north in both the examples. Hence in (1) b=8+5=13
(north) and in (2) b=4+5=9 (north). Refering to Fig. 60,
we see there three cases depicted namely the extremi-