सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)
Siddhanta Shiromani Ganitadhyaya of Bhaskaracharya with Commentary
भास्कराचार्य द्वितीय द्वारा
पृष्ठ 277, कुल 573 में से
संदर्भ में पढ़ें257
In the parallel great circle, the Equator we have
therefore Antyā = Charajyā + R (already derived).
Verse 35. Antyā = (Hṛti × R) / (H cos δ) = (Hṛti × Charajyā) / Kujyā and
∴ Hṛti = (Antyā × H cos δ) / R = (Antyā × Kujyā) / Charajyā by what is
called Guṇa-ccheda-Viparyaya ie. alternando.
Comm. Evident.
Verse 36. To obtain Dinārdha-Śaṅku from Antyā
and Hṛti
(Antyā × un-maṇḍala Śaṅku) / Charajyā = (Hṛti × 12) / K = Dinārdha-
Śaṅku.
Comm. The second formula is derived from the
similarity of △ Ao₄a (fig.) with the first latitudinal triangle.
From the similarity of Aao₄, Ddo₄ fig. 39,
Ao₄/Do₄ = Aa / Dd ∴ Aa = (Hṛti × unmaṇḍala-Śaṅku) / Kujyā .
But Aa = Dinārdha-Śaṅku
∴ Dinārdha Śaṅku = (Hṛti × U.S.) / Kujyā (U. S. = Un-
maṇḍala-Śaṅku.)
But Hṛti / Kujyā = Antyā / Charajyā
∴ D.S. (Dinārdha-Śaṅku) = Charajyā / Antyā × U.S.
= (Hṛti × 12) / K VIII.
Verse 37. Meridian Zenith distance.
Agrā ± (Hṛti × bhuja of a lat. triangle) / (Karṇa of a lat. triangle) = H sin z
where z is the meridian zenith distance.
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