सङ्गीतरत्नाकर: प्रथम भाग (शार्ङ्गदेव - स्वरगताध्याय सविस्तार व्याख्या व अनुवाद सहित)
Sangita Ratnakara of Sarangadeva (Svaradhyaya)
शार्ङ्गदेव (अनुवादक: डॉ. आर. के. श्रृङ्गी एवं डॉ. प्रेमलता शर्मा) द्वारा
पृष्ठ 136, कुल 251 में से
संदर्भ में पढ़ें220 Treatment of Svara
respective notes with reference to the last note of the original
order¹⁰; while the rule for dropping the ascertained note
etc.¹¹ would apply as before.¹² (68c-70)
5. We get these numbers in the series 1-2-3-3 corresponding to
the serial number of squares in the respective columns. Now relate this
series to the original order "sa-ri-ga-ma". Place ri as the last note of
the 'missing note-series', for it is 3rd from ma, the last note of the
original series.
6. Drop ri and restore the original order to "sa-ga-ma" and the
numbers in the series to 1-2-3 Then repeat the process.
7. Place sa anterior to ri in the process of finding out the 'missing
note-series' as sa is 3rd from ma.
8. Drop sa and 3 respectively from the original order and the
numerical series, and then restore them to "ga-ma" and 1-2 respectively
and repeat the process.
9. Place ga anterior to "sa-ri" discovered through the process,
for ga is 2nd to ma in the original order and corresponds to the figure 2
in the given numerical series. So we get "ga sa ri".
10. Drop ga from the original order and 2 from the numerical
series. Now we are left with ma which corresponds to 1 of the numerical
series and the left-end square of the 1st series i. e., the first column
square. So put ma anterior to "ga sa ri" already obtained. We get
"ma ga sa ri".
11. The 'lost note-series' is discovered to be "ma ga sa ri" which
corresponds to its given serial number 18 in the tetratonic series.
It will be observed that wherever the original order coincides with
the numerical series the note-position of the tone in question remains
the same.
An example of a complete permutational note-series is also
demonstrated in the following chart.
(i) The problem : To find out the tonal form of the 'missing
note-series' of heptatonic type bearing serial No. 1000.
10. The original order corresponds to the mūrcchanā-series.
11. At every step as in the case of uddiṣṭa, i. e., the process of the
indicated note-series, the note ascertained would be dropped
out of view.
12. 'S' infers that 'etc.' in the text is indicative of the direction
that, with the 'missing note-series' of, say five notes, the
permutation indicator will have five series of square-columns,
that of six notes will have six and that of seven will have
seven
Section 4 : Grāma, Mūrcchanā, ...
(ii) The original order : "sa ri ga ma pa dha ni".
(iii) Procedure in action.
Discovering the 'lost note-series' of complete permutational note-series
| Col. squares add upto 1000 1 | Relative position of notes 2 | Effect of action 3 | Order of discovered notes 4 |
|---|---|---|---|
| Col. No. (a) | Sq. No. (b) | Figure (c) | Last note of the original order (a) | Corresponding note of the given series found as per 1 (b) [Note (i) | Position (ii)] | Note ropped (a) | Order of the original series restored (b) | |
| 7 | 2 | 720 | ni | dha | 7th | dha | sa-ri-ga-ma-pa-ni | 000000 dha |
| 6 | 3 | 240 | ni | ma | 6th | ma | sa-ri-ga-pa-ni | 00000 ma dha |
| 5 | 2 | 24 | ni | pa | 5th | pa | sa-ri-ga-ni | 0000 pa-ma-dha |
| 4 | 3 | 12 | ni | ri | 4th | ri | sa-ga-ni | 000 ri-pa-ma-dha |
| 3 | 2 | 2 | ni | ga | 3rd | ga | sa-ni | 00 ga-ri-pa-ma-dha |
| 2 | 2 | 1 | ni | sa | 2nd | sa | ni | 0 sa-ga-ri-pa-ma dha |
| 1 | 1 | 1 | ni | ni | 1st | ni | — | ni-sa-ga-ri-pa-ma-dha |
| (Chart 26) | |||
| (iv) Thus the 1000th note-series is discovered to be "ni-sa-ga-ri-pa ma-dha" in the complete series. | |||
| *Explanation : The computation of this column of the chart is explained as under, step by step : | |||
| (i) Deduct 1 of the first square column which is essentially to be taken 1000 - 1 = 999. Now we have to make up the total for 999. | |||
| (ii) Take 720 in column 7 as the next square below given 1440 which exceeds 999. Deduct 720 from 999 (999-720 = 279). Thus we have to add upto 279 now. | |||
| (iii) Take 240 from column 6 for the next square offers 360 which exceeds 279. Now we have (279-240 =) 39 to add up. | |||
| (iv) Similarly, take 24 from column 5 and we have (39-24 =) 15 more to add up. | |||
| (v) Then take 12 from column 4 and we have (15-12 =) 3 more to add up. | |||
| (vi) Then take 2 from column 3 and we have 1 more to add. | |||
| (vii) Finally take 1 from column 2 and get the columnwise total as 720+240+24+12+2+1+1 = 1000. |