ब्राह्मस्फुटसिद्धान्त (ब्रह्मगुप्त - शून्य, कुट्टक, बीजगणित एवं सम्पूर्ण २१ अध्याय सान्वय सटीक)
Brahmasphuta Siddhanta of Brahmagupta with Commentary
by आचार्य ब्रह्मगुप्त
Page 286 of 737
Read in context240 BRAHMAGUPTA AS AN ALGEBRAIST
If the multiplier be negative, it must be made positive;
and the additive must be made negative : and then the
method of the pulveriser should be employed.
Pṛthūdaka Svāmī, however, does not indicate how to derive
the solution of the equation.
by = -ax+c ...(1)
from that of the equation
by = ax-c ...(2)
The method, however, seems to have been this :
Let x=α, y=β be the minimum solution of (2). Then
we get
bβ = a α-c
or b(a-β) = -a(a-b)+c
Hence x=a-b, y=a-β is the minimum solution of (1). This
rule is very clearly indicated by Bhāskara II and others.
We shall give two examples from Bhāskara II (Bījagaṇita)
to illustrate the rule :
Example I.
13y = -60x + 3
By the method described before, we find that the minimum
solution of
13y = 60x+3
is x=11, y=51. Subtracting these values from their respective
abraders, namely 13 and 60, we get 2 and 9. Then by the
maxim : "In the case of the dividend and divisor being of differ-
ent signs, the results from the operation of division should be
known to be so", making the quotient negative we get the solu-
tion of
13y = -60x+3
as x=2, y=-9. Subtracting these values again from their respec-
tive abraders (13, 60), we get the solution of
13y = -60x-3
as x=11, y=-51.
Example II.
11y = 18x+10